Well, white cannot stop black from queening h-pawn. So, white has to find a way to mate black with black's queen on the board. It seems, fortunately, that white indeed has a way to achieve this:
1. Ne7+! Kb5 (only move) 2. Kb7!! (restricting black king and making room for his knight on c8) 2....h1Q 3. Nc8 with the threats of Na7# and Nxd6#. Black queen can not stop both these mates at the same time.
and white has two mating metthods and black can only prevent one
Na7 and Bb6 or Nxd6 and Bb6
This is an easy puzzle and if I reached this positionin a game I am sure I would find it.
But if I was analysing a line that led to this position I probably wouldn't have glanced twice at it, and would have written the line off as winning for black. One of the many reasons I am not a GM :)
Don't see where the difficulty lies in this one. After obvious 1. Ne7+, Black's 1... Kb5 is forced. Then 2. Kb7 cuts off all escape squares from the Black king except a5, which the bishop will take care of. Then if Black plays 2... h1=Q, White plays 3. Nc8, ready to deliver check on d6 or a7 depending on what Black does next. If Black plays 3... Qh2 to prevent Nxd6+, then White plays 4. Na7+ with mate next move. If Black plays 3... Qa1 to prevent Na7+, then White plays 4. Nxd6+ with mate next move. If Black starts out by trying to promote the e-pawn, Cinderella may turn into a princess, but too late to save the game. White still plays 1. Ne7+, 2. Kb7, 3. Nxd6+ or 3. Na7+ (doesn't matter which) and mate next move (4. Bb6#).
10 comments:
I think:
1. Ne7+ Kb5
2. Kb7 h1=Q
3. Nxd5
if
3. ... Q moves
4. Nc7+ Ka5
5. Bb6 mate
if
3. ... Ka5
4. Bb6+ Kb5
5, Nc7 mate
1. Ne7 Kb5 2. Kb7 puts the black king in a mating net.
2...h1=Q 3. Nc8 and black is helpless against 4. Na7 and 5. Bb6 mate.
My previous post fails since the new queen controls the d5 square..so I think this is the win:
1. Ne7+ Kb5
2. Kb7 h1=Q
3. Nc8! mate next move
1.Ne7+ seems to lead to mate
1...Kb5
2.Kb7! h1=Q
3.Nc8 and black cant defend both Nxe6+ and Na7+ followed by Bb6#
Well, white cannot stop black from queening h-pawn. So, white has to find a way to mate black with black's queen on the board. It seems, fortunately, that white indeed has a way to achieve this:
1. Ne7+! Kb5 (only move)
2. Kb7!! (restricting black king and making room for his knight on c8)
2....h1Q
3. Nc8 with the threats of Na7# and Nxd6#. Black queen can not stop both these mates at the same time.
Hope I did not miss anything here :)
1.Ne7+ Kb5 2.Kb7 h1Q
[2...Ka5 3.Bb6+ Kb5 4.Nc6 h1Q 5.Na7#]
3.Nc8
[3.Nc6 Qa1 4.Na7 Qxa1]
3...Qa1 4.Nxd6#
- SS
Ne7 Kb6
Kb7 a1=Q
Nc8
and white has two mating metthods and black can only prevent one
Na7 and Bb6
or
Nxd6 and Bb6
This is an easy puzzle and if I reached this positionin a game I am sure I would find it.
But if I was analysing a line that led to this position I probably wouldn't have glanced twice at it, and would have written the line off as winning for black. One of the many reasons I am not a GM :)
Don't see where the difficulty lies in this one. After obvious 1. Ne7+, Black's 1... Kb5 is forced. Then 2. Kb7 cuts off all escape squares from the Black king except a5, which the bishop will take care of. Then if Black plays 2... h1=Q, White plays 3. Nc8, ready to deliver check on d6 or a7 depending on what Black does next. If Black plays 3... Qh2 to prevent Nxd6+, then White plays 4. Na7+ with mate next move. If Black plays 3... Qa1 to prevent Na7+, then White plays 4. Nxd6+ with mate next move. If Black starts out by trying to promote the e-pawn, Cinderella may turn into a princess, but too late to save the game. White still plays 1. Ne7+, 2. Kb7, 3. Nxd6+ or 3. Na7+ (doesn't matter which) and mate next move (4. Bb6#).
Lucy
1.Ne7+ Kb5 2.Kb7 h1(Q) 3.Nc8 threatening 4.Na7+ or 4.Nxd6+ and 5.Bb6#
mmh, because I always solve (or misunderstand) these problems during my office time ;-) I have to calculate everything without a board.
I suggest:
1. Ne7+ Kb5
2. Kb7 h1Q
3. Nc8 Qa1
4. Nd6 mate
3. Qh2
4. Ba7 mate
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